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9x+162=3x^2
We move all terms to the left:
9x+162-(3x^2)=0
determiningTheFunctionDomain -3x^2+9x+162=0
a = -3; b = 9; c = +162;
Δ = b2-4ac
Δ = 92-4·(-3)·162
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-45}{2*-3}=\frac{-54}{-6} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+45}{2*-3}=\frac{36}{-6} =-6 $
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